[ Log In ]

16x2 LCD (Liquid Crystal Display)

16x2 LCD (Liquid Crystal Display)

$12.50
Qty:
Newbie Hack Shirt Back
Front of the 128x64 display module

128x64 OLED Display Yel/Blu

$17.95
Qty:
Red Through Hole LED (Light emitting diode)

Single Red Through Hole LED (Light Emitting Diode)

$0.34
Qty:
Green through hole LED (light emitting diode)

Single Green Through Hole LED (Light Emitting Diode)

$0.34
Qty:
Yellow through hole LED (light emitting diode)

Single Yellow Through Hole LED (Light Emitting Diode)

$0.34
Qty:
thumbnail: 8 channel logic analyzer - iLogic

4 Channel Logic Analyzer

$149.00
Qty:
Thumbnail: quad buffer line driver 74HC126E

Quad Buffer Line Driver (Through Hole)

$0.69
Qty:
Small red knob for potentiometer

Small Knob for Potentiometer - Black with Red Cap

$0.94
Qty:

Red Through Hole LED (Light Emitting Diode)

Red Through Hole LED (Light Emitting Diode)
Red Through Hole LED (Light Emitting Diode)

Introduction:

An output device that emits red light when 2V power is applied.

Description:

Use this LED with a resistor (if the voltage applied is more than 2V). LEDs can provide indication in many forms and applications such as larger displays that consists of many LEDs, or indication lights to inform of a particular state. Low power consumption and RoHS compliant.

Single Red Through Hole LED (Light Emitting Diode)

$0.34
Qty:

Learn about the Red Through Hole LED (Light Emitting Diode)

Part 1: Making a circuit for the Atmel AVR Atmega32 microcontroller to light up an LED (Light Emitting Diode). The circuit consists of an LED, a resistor of the appropriate value to limit current to ...
Making the simple circuit to connect an LED (Light Emitting Diode) with a resistor to an Atmel AVR Atmega32 microcontroller connected to PORTB Pin 0.
The schematic symbol of an LED (Light Emitting Diode).
How to determine the polarity of an LED (Light Emitting Diode) and determine which lead is the anode and cathode.
LED (Light Emitting Diode) colors, their voltages and how to select a resistance value for an LED so the LED will not have more current than it needs (will not burn out).